document.write( "Question 26196: The perimeter of a rectangle is 16 feet. The width is 2 feet less than the length. Find the width. \n" ); document.write( "
Algebra.Com's Answer #14071 by stanbon(75887)\"\" \"About 
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Let the length be \"x\".
\n" ); document.write( "Then the width is \"x-2\"
\n" ); document.write( "Formula: perimeter = 2l+2w
\n" ); document.write( "16=2x+2(x-2)
\n" ); document.write( "8=x+x-2
\n" ); document.write( "10=2x
\n" ); document.write( " x=5 feet (this is the length)
\n" ); document.write( "x-2=3 feet (this is the width)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.\r
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