document.write( "Question 187617: flight 725 left new york at 10:28am flying north. flight 245 left same airport at 11:18am flying south at 125kmh less than 3 times the speed of flight 725. at 1:06pm they are 1030 km apart. what is average rate of speed for flight 245? \n" ); document.write( "
Algebra.Com's Answer #140672 by ankor@dixie-net.com(22740)\"\" \"About 
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flight 725 left new york at 10:28am flying north. flight 245 left same airport
\n" ); document.write( " at 11:18am flying south at 125kmh less than 3 times the speed of flight 725.
\n" ); document.write( " at 1:06pm they are 1030 km apart. what is average rate of speed for flight 245?
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\n" ); document.write( "Let s = speed of flt 725
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\n" ); document.write( "then is says,\"flt 245 flies 125kmh less than 3 times the speed of flight 725.\"
\n" ); document.write( "therefore:
\n" ); document.write( "(3s-125) = speed of flt 245
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\n" ); document.write( "Travel times of both aircraft (Change 1:06 to 13:06):
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\n" ); document.write( "Flt 725: 13:06 - 10:28 = 2 hr 38 min ~ 2.633 hrs
\n" ); document.write( "Flt 245: 13:06 - 11:18 = 1 hr 48 min = 1.8 hrs
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\n" ); document.write( "Write a dist equation: dist = time * speed
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\n" ); document.write( "Flt 725 dist + Flt 245 dist = 1030 km
\n" ); document.write( "2.633s + 1.8(3s-125) = 1030
\n" ); document.write( "2.633s + 5.4s - 225 = 1030
\n" ); document.write( "2.633s + 5.4s = 1030 + 225
\n" ); document.write( "8.033s = 1255
\n" ); document.write( "s = \"1255%2F8.033\"
\n" ); document.write( "s = 156.23 km/hr is the speed of flt 725
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\n" ); document.write( "but they want the speed of 245
\n" ); document.write( "3(156.23) - 125 = 343.69 km/hr is the speed of flt 245
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\n" ); document.write( "Check solution by finding the distance of each at 1:06
\n" ); document.write( "2.633 * 156.23 =411.35
\n" ); document.write( "1.8 * 343.69 = 618.64
\n" ); document.write( "-------------------------
\n" ); document.write( "total distance = 1029.99 ~ 1030; confirms our solutions
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