document.write( "Question 187633This question is from textbook algebra 1
\n" ); document.write( ": helow
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\n" ); document.write( " who can help me to find the answer with a solution of this given\r
\n" ); document.write( "\n" ); document.write( "y=-4x+3
\n" ); document.write( "5y=10x=20
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Algebra.Com's Answer #140660 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
I can!...but first, since you wrote \"5y=10x=20\" did you really mean to write:
\n" ); document.write( "\"5y+=+10x%2B20\" or
\n" ); document.write( "\"highlight%285y%2B10x+=+20%29\" ???
\n" ); document.write( "I suspect the latter is what you meant so I'll use that, but if I'm wrong, please resubmit with the appropriate correction.
\n" ); document.write( "Solve:
\n" ); document.write( "1) \"y+=+-4x%2B3\"
\n" ); document.write( "2) \"5y%2B10x+=+20\"
\n" ); document.write( "Substitute equation 1) for y into equation 2) to get:
\n" ); document.write( "2a) \"5%28-4x%2B3%29%2B10x+=+20\" Simplify and solve for x.
\n" ); document.write( "2a) \"-20x%2B15%2B10x+=+20\"
\n" ); document.write( "2a) \"-10x%2B15+=+20\"
\n" ); document.write( "2a) \"-10x+=+5\"
\n" ); document.write( "2a) \"highlight%28x+=+-1%2F2%29\" Now substitute this value of x into equation 1) and find y.
\n" ); document.write( "1) \"y+=+-4x%2B3\" Substitute \"x+=+-1%2F2\"
\n" ); document.write( "1) \"y+=+-4%28-1%2F2%29%2B3\" Evaluate the right side.
\n" ); document.write( "1) \"y+=+2%2B3\"
\n" ); document.write( "1) \"highlight%28y+=+5%29\"
\n" ); document.write( "The solution: (-1/2, 5)
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