document.write( "Question 187624: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #140654 by user_dude2008(1862) ![]() You can put this solution on YOUR website! \"Mike invested $6000 for one year\" ----> x+y=6000 ----> y=6000-x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest\" ----> 0.09x+0.11y=624 ----> 9x+11y=62400\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x+11y=62400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x+11(6000-x)=62400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x+66000-11x=62400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2x+66000=62400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2x=62400-66000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2x=-3600\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=1800\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "He invested $1,800 at 9%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=6000-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=6000-1800\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=4200\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "He invested $4,200 at 11% \n" ); document.write( " |