document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187526>Question 187526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cruise boat travels 48 miles downstream in 3 hours and returns upstream in 6 hours.  Find the rate of the stream. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140643 by </B><A HREF=/tutors/aboutme.mpl?userid=dukesmart><B>dukesmart(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dukesmart><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x= cruise ship speed; y = stream speed\r<BR>\n" );
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document.write( "we can establish the equation as follows:\r<BR>\n" );
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document.write( "(x+y)*3 = 48 ========> x + y = 16 ......(1)\r<BR>\n" );
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document.write( "(x-y)*6 = 48 ========> x - y =  8 ......(2)\r<BR>\n" );
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document.write( "Take (1) add  (2) we will have : 2x = 24<BR>\n" );
document.write( "                                  x = 12<BR>\n" );
document.write( "Therefore     y = 16-12    <BR>\n" );
document.write( "              y = 4<BR>\n" );
document.write( "Answer : the rate of the stream is 4 miles/hour.<BR>\n" );
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