document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187609>Question 187609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. If the area of the rectangle is 200yd^2  , find its perimeter. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140621 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W<BR>\n" );
document.write( "LW=200<BR>\n" );
document.write( "2W*W=200<BR>\n" );
document.write( "2W^2=200<BR>\n" );
document.write( "W^2=200/2<BR>\n" );
document.write( "W^2=100<BR>\n" );
document.write( "W=SQRT100<BR>\n" );
document.write( "W=10 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*10=20 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PERIMETER=2L+2W<BR>\n" );
document.write( "P=2*20+2*10=40+20=60 YDS. IS THE PERIMETER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );