document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187583>Question 187583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is fifteen. One less than three times the smaller is equal to the larger. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140601 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is fifteen. One less than three times the smaller is equal to the larger. Find the two numbers.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 15<BR>\n" );
document.write( "3x - 1 = y<BR>\n" );
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document.write( "Substitute 3x-1 in place of \"y\" to solve for \"x\":<BR>\n" );
document.write( "x + 3x-1 = 15<BR>\n" );
document.write( "4x = 16<BR>\n" );
document.write( "x = 4<BR>\n" );
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document.write( "Substitute to solve for \"Y\":<BR>\n" );
document.write( "y = 3*4-1 = 11<BR>\n" );
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document.write( "Solution: (4,11)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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