document.write( "Question 187524: Solve the problem: Joe has a collection of nickels and dimes that is worth $6.00. If the number of dimes was doubled and the number of nickels was increased by 6, the value of the coins would be $9.90.\r
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document.write( "How many dimes does he have?
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Algebra.Com's Answer #140595 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! oe has a collection of nickels and dimes that is worth $6.00. \n" ); document.write( " If the number of dimes was doubled and the number of nickels was increased by 6, \n" ); document.write( " the value of the coins would be $9.90. \n" ); document.write( "How many dimes does he have? \n" ); document.write( ": \n" ); document.write( "Let n = no. of nickels; Let d = no. of dimes (originally) \n" ); document.write( ": \n" ); document.write( "\"a collection of nickels and dimes that is worth $6.00.\" \n" ); document.write( ".05n + .10d = 6.00 \n" ); document.write( "or \n" ); document.write( ".05n = 6.00 - .10d \n" ); document.write( "n = \n" ); document.write( "n = 120 - 2d \n" ); document.write( ": \n" ); document.write( "\"If the number of dimes was doubled and the number of nickels was increased by 6, the value of the coins would be $9.90.\" \n" ); document.write( ".05(n+6) + 2(.10d) = 9.90 \n" ); document.write( ".05n + .3 + .20d = 9.90 \n" ); document.write( ".05n + .20d = 9.90 - .3 \n" ); document.write( ".05n + .20d = 9.60 \n" ); document.write( ": \n" ); document.write( "Substitute (120-2d) for n in the above equation: \n" ); document.write( ".05(120-2d) + .20d = 9.60 \n" ); document.write( "6 - .10d + .20d = 9.60 \n" ); document.write( "-.10d + .20d = 9.60 - 6 \n" ); document.write( ".10d = 3.60 \n" ); document.write( "d = \n" ); document.write( "d = 36 dimes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Find the no. of nickels to check our solution \n" ); document.write( "n = 120 - 2d \n" ); document.write( "n = 120 - 2(36) \n" ); document.write( "n = 120 - 72 \n" ); document.write( "n = 48 nickels \n" ); document.write( "; \n" ); document.write( ".05(48) + .10(36) = \n" ); document.write( "2.40 + 3.60 = 6.00; confirms our solution \n" ); document.write( " |