document.write( "Question 187524: Solve the problem: Joe has a collection of nickels and dimes that is worth $6.00. If the number of dimes was doubled and the number of nickels was increased by 6, the value of the coins would be $9.90.\r
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Algebra.Com's Answer #140595 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
oe has a collection of nickels and dimes that is worth $6.00.
\n" ); document.write( " If the number of dimes was doubled and the number of nickels was increased by 6,
\n" ); document.write( " the value of the coins would be $9.90.
\n" ); document.write( "How many dimes does he have?
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\n" ); document.write( "Let n = no. of nickels; Let d = no. of dimes (originally)
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\n" ); document.write( "\"a collection of nickels and dimes that is worth $6.00.\"
\n" ); document.write( ".05n + .10d = 6.00
\n" ); document.write( "or
\n" ); document.write( ".05n = 6.00 - .10d
\n" ); document.write( "n = \"6%2F.05\" - \".10%2F.05\"d
\n" ); document.write( "n = 120 - 2d
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\n" ); document.write( "\"If the number of dimes was doubled and the number of nickels was increased by 6, the value of the coins would be $9.90.\"
\n" ); document.write( ".05(n+6) + 2(.10d) = 9.90
\n" ); document.write( ".05n + .3 + .20d = 9.90
\n" ); document.write( ".05n + .20d = 9.90 - .3
\n" ); document.write( ".05n + .20d = 9.60
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\n" ); document.write( "Substitute (120-2d) for n in the above equation:
\n" ); document.write( ".05(120-2d) + .20d = 9.60
\n" ); document.write( "6 - .10d + .20d = 9.60
\n" ); document.write( "-.10d + .20d = 9.60 - 6
\n" ); document.write( ".10d = 3.60
\n" ); document.write( "d = \"3.6%2F.1\"
\n" ); document.write( "d = 36 dimes
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\n" ); document.write( "Find the no. of nickels to check our solution
\n" ); document.write( "n = 120 - 2d
\n" ); document.write( "n = 120 - 2(36)
\n" ); document.write( "n = 120 - 72
\n" ); document.write( "n = 48 nickels
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\n" ); document.write( ".05(48) + .10(36) =
\n" ); document.write( "2.40 + 3.60 = 6.00; confirms our solution
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