document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187569>Question 187569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to factor this problem I just am not sure how to since it has to exponents. <BR>\n" );
document.write( "9b^3 – 6b^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140587 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to factor this problem I just am not sure how to since it has to exponents. <BR>\n" );
document.write( "9b^3 – 6b^2<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "You can do it in steps, just look for a common factor.  Both terms have a b, so<BR>\n" );
document.write( "9b^3 - 6b^2 = b*(9b^2 - 6b)<BR>\n" );
document.write( "They still both have a b<BR>\n" );
document.write( "= b^2*(9b - 6)  All the b's are out.  Now there's a 3.<BR>\n" );
document.write( "= 3b^2*(3b - 2)<BR>\n" );
document.write( "That's all.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );