document.write( "Question 187498: I need to solve the following equation:\r
\n" ); document.write( "\n" ); document.write( "1/b-3 = b/4 \n" ); document.write( "

Algebra.Com's Answer #140557 by checkley77(12844) $\"\"$ $\"About$

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1/b-3 = b/4
\n" ); document.write( "(1-3b)/b=b/4
\n" ); document.write( "b^2=4(1-3b)
\n" ); document.write( "b^2=4-12b
\n" ); document.write( "b^2+12b-4=0
\n" ); document.write( " $\"b+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "b=(-12+-sqrt[12^2-4*1*-4])/2*1
\n" ); document.write( "b=(-12+-sqrt[144+16])/2
\n" ); document.write( "b=(-12+-sqrt160)/2
\n" ); document.write( "b=(-12+-12.649)/2
\n" ); document.write( "b=(-12+12.649)/2
\n" ); document.write( "b=.649/2
\n" ); document.write( "b=.3246 ans.
\n" ); document.write( "b=.649/2
\n" ); document.write( "b=(-12-12.649)/2
\n" ); document.write( "b=-24.649/2
\n" ); document.write( "-12.3246 ans. \n" ); document.write( "

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