document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187505>Question 187505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not understand the process for working out problems such as (2x-5)^3.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140543 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I do not understand the process for working out problems such as (2x-5)^3.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Pascal’s triangle which is nothing more than 11 raised to various powers but any values greater than 9 are not carried over to the next column. You add adjoining numbers to get the numbers for the next row which is easier if you have it constructed as a triangle widening equally on both sides as each number equals the sum of the two numbers above it on either side.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "For the power of 0 : 1<BR>\n" );
document.write( "For the power of 1 : 1,1<BR>\n" );
document.write( "For the power of 2 : 1,2,1 from 1, 1+1, 1<BR>\n" );
document.write( "For the power of 3 : 1,3,3,1 from 1, 1+2, 2+1, 1<BR>\n" );
document.write( "For the power of 4 : 1,4,6,4,1 from 1, 1+3, 3+3, 3+1, 1<BR>\n" );
document.write( "For the power of 5 : 1,5,10,10,5,1 from 1, 1+4, 4+6, 6+4, 4+1, 1<BR>\n" );
document.write( "etc.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "11^0 = 1<BR>\n" );
document.write( "11^1 = 11<BR>\n" );
document.write( "11^2 = 121<BR>\n" );
document.write( "11^3 = 1331<BR>\n" );
document.write( "11^4 = 14641<BR>\n" );
document.write( "11^5 = 15(10)(10)51 = 161051 after carrying the tens over<BR>\n" );
document.write( "etc.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So this is how you expand (a + b)^n.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "For (a + b)^3 we will use coefficients 1, 3, 3, 1.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Therefore (2x – 5)^3 =\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(2x)^3 + 3(2x)^2(-5) + 3(2x)(-5)^2 + (-5)^3 =\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "8x^3 – 60x^2 + 150x - 125 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );