document.write( "Question 26123: I tried this by myself, but it didn't work out. Here is the question and the way I set it up. \r
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document.write( "If Jolly Janet has 0.5% saline to mix with 7.5% saline, how much of each is needed to get 200L of 1.0% saline?\r
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document.write( "I set it up like this:\r
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document.write( ".005X + .075(200-X)=.001(200)\r
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document.write( "I know this is wrong, but could you tell me the correct way to set it up?
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document.write( "Thanks. \n" );
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Algebra.Com's Answer #14050 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! YOU always put the middle number on the right side\r \n" ); document.write( "\n" ); document.write( "75x-200=5(200-x) \n" ); document.write( "75x-200=1000-5x \n" ); document.write( "80x=1200 \n" ); document.write( "x=15 \n" ); document.write( "200-15=185\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, for 7.5% about 15L is needed and for 0.5% about 185L is needed. \n" ); document.write( "PAUL. \n" ); document.write( " |