document.write( "Question 26123: I tried this by myself, but it didn't work out. Here is the question and the way I set it up. \r
\n" ); document.write( "\n" ); document.write( "If Jolly Janet has 0.5% saline to mix with 7.5% saline, how much of each is needed to get 200L of 1.0% saline?\r
\n" ); document.write( "\n" ); document.write( "I set it up like this:\r
\n" ); document.write( "\n" ); document.write( ".005X + .075(200-X)=.001(200)\r
\n" ); document.write( "\n" ); document.write( "I know this is wrong, but could you tell me the correct way to set it up?
\n" ); document.write( "Thanks.
\n" ); document.write( "

Algebra.Com's Answer #14050 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
YOU always put the middle number on the right side\r
\n" ); document.write( "\n" ); document.write( "75x-200=5(200-x)
\n" ); document.write( "75x-200=1000-5x
\n" ); document.write( "80x=1200
\n" ); document.write( "x=15
\n" ); document.write( "200-15=185\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, for 7.5% about 15L is needed and for 0.5% about 185L is needed.
\n" ); document.write( "PAUL.
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