document.write( "Question 187380: a ball is thrown into the air in such a way that its distance(d), in feet, above the ground at any time(t), in seconds, is given by the equation d=40t-5t^2.\r
\n" );
document.write( "\n" );
document.write( "how many seconds will it take for the ball to reach a height of 80ft above the ground? \n" );
document.write( "
Algebra.Com's Answer #140496 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! d=40t-5t^2. \n" ); document.write( "80=40T-5T^2 \n" ); document.write( "5T^2-40T+80=0 \n" ); document.write( "5(T^2-8T+16)=0 \n" ); document.write( "5(T-4)(T-4)=0 \n" ); document.write( "T-4=0 \n" ); document.write( "T=4 SEC. ANS. \n" ); document.write( "PROOF: \n" ); document.write( "80=40*4-5*4^2 \n" ); document.write( "80=160-5*8 \n" ); document.write( "80=160-80 \n" ); document.write( "80=80 \n" ); document.write( " |