document.write( "Question 187380: a ball is thrown into the air in such a way that its distance(d), in feet, above the ground at any time(t), in seconds, is given by the equation d=40t-5t^2.\r
\n" ); document.write( "\n" ); document.write( "how many seconds will it take for the ball to reach a height of 80ft above the ground?
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Algebra.Com's Answer #140496 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
d=40t-5t^2.
\n" ); document.write( "80=40T-5T^2
\n" ); document.write( "5T^2-40T+80=0
\n" ); document.write( "5(T^2-8T+16)=0
\n" ); document.write( "5(T-4)(T-4)=0
\n" ); document.write( "T-4=0
\n" ); document.write( "T=4 SEC. ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "80=40*4-5*4^2
\n" ); document.write( "80=160-5*8
\n" ); document.write( "80=160-80
\n" ); document.write( "80=80
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