document.write( "Question 187402: A freight train covered 120 miles at a certain speed. Had the train been able to travel 10 mph faster, the trip would have been 2 hours shorter. How fast did the train go? \n" ); document.write( "
Algebra.Com's Answer #140495 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D/R=T
\n" ); document.write( "120/X=T
\n" ); document.write( "120/(X+10)=T-2
\n" ); document.write( "NOW REPLACE T WITH 120/X IN THE SECOND EQUATION & SOLVE FOR X.
\n" ); document.write( "120/(X+10)=(120/X)-2
\n" ); document.write( "120/(X+10)=(120-2X)/X NOW CROSS MULTIPLY.
\n" ); document.write( "(X+10)(120-2X)=120X
\n" ); document.write( "120X+1200-20X-2X^2=120X
\n" ); document.write( "-2X^2+100X+1200-120X=0
\n" ); document.write( "-2X^2-20X+1200=0
\n" ); document.write( "-2(X^2+10X-600)=0
\n" ); document.write( "-2(X-20)(X+30)=0
\n" ); document.write( "X-20=0
\n" ); document.write( "X=20 MPH. ANS. FOR THE FIRST 120 MILE TRIP.
\n" ); document.write( "20+10=30 MPH. ANS. FOR THE FASTER TRIP.
\n" ); document.write( "PROOF:
\n" ); document.write( "120/30=(120/20)-2
\n" ); document.write( "4=6-2
\n" ); document.write( "4=4
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