document.write( "Question 187402: A freight train covered 120 miles at a certain speed. Had the train been able to travel 10 mph faster, the trip would have been 2 hours shorter. How fast did the train go? \n" ); document.write( "
Algebra.Com's Answer #140495 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D/R=T \n" ); document.write( "120/X=T \n" ); document.write( "120/(X+10)=T-2 \n" ); document.write( "NOW REPLACE T WITH 120/X IN THE SECOND EQUATION & SOLVE FOR X. \n" ); document.write( "120/(X+10)=(120/X)-2 \n" ); document.write( "120/(X+10)=(120-2X)/X NOW CROSS MULTIPLY. \n" ); document.write( "(X+10)(120-2X)=120X \n" ); document.write( "120X+1200-20X-2X^2=120X \n" ); document.write( "-2X^2+100X+1200-120X=0 \n" ); document.write( "-2X^2-20X+1200=0 \n" ); document.write( "-2(X^2+10X-600)=0 \n" ); document.write( "-2(X-20)(X+30)=0 \n" ); document.write( "X-20=0 \n" ); document.write( "X=20 MPH. ANS. FOR THE FIRST 120 MILE TRIP. \n" ); document.write( "20+10=30 MPH. ANS. FOR THE FASTER TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "120/30=(120/20)-2 \n" ); document.write( "4=6-2 \n" ); document.write( "4=4 \n" ); document.write( " \n" ); document.write( " |