document.write( "Question 187395: After 13 years, 2.1 pounds of radioactive material remains from a 7 pound sample. What is the half-life of this material? \n" ); document.write( "
Algebra.Com's Answer #140469 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! After 13 years, 2.1 pounds of radioactive material remains from a 7 pound sample. What is the half-life of this material? \n" ); document.write( "------------------------------------ \n" ); document.write( "A(t) = A(0)(1/2)^(13/h)t \n" ); document.write( "2.1 = 7 (1/2)^(13/h)t \n" ); document.write( "0.3 = (1/2)^(13/h) \n" ); document.write( "Take the log to get: \n" ); document.write( "(13/h)log(0.5) = log(0.3) \n" ); document.write( "(13/h) = [log(0.3)]/[log(0.5)] \n" ); document.write( "13/h = 1.7370 \n" ); document.write( "h = 13/1.7370 \n" ); document.write( "h = 7.4843 years (this is the half-life of the material) \n" ); document.write( "------------------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |