document.write( "Question 187350: How many different committees of 4 each can be chosen from a class of 15 members?\r
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\n" ); document.write( "\n" ); document.write( "Please give the solution so I can understand it.. thanks^^
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Algebra.Com's Answer #140467 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
How many different committees of 4 each can be chosen from a class of 15 members?
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\n" ); document.write( "The 1st choice is 1 of 15, the 2nd 1 of 14, 13, 12.
\n" ); document.write( "15*14*13*12 = 32760
\n" ); document.write( "But, choosing ABCD is the same as ADCB or ACBD, etc, so you have to divide by 4*3*2*1, which is 24
\n" ); document.write( "32760/24 = 1365 possibilities.
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\n" ); document.write( "This is 15!/((15-4)!*4!)
\n" ); document.write( "! is factorial, and it's on most calculators.
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