document.write( "Question 187350: How many different committees of 4 each can be chosen from a class of 15 members?\r
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document.write( "Please give the solution so I can understand it.. thanks^^ \n" );
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Algebra.Com's Answer #140467 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How many different committees of 4 each can be chosen from a class of 15 members? \n" ); document.write( "----------------- \n" ); document.write( "The 1st choice is 1 of 15, the 2nd 1 of 14, 13, 12. \n" ); document.write( "15*14*13*12 = 32760 \n" ); document.write( "But, choosing ABCD is the same as ADCB or ACBD, etc, so you have to divide by 4*3*2*1, which is 24 \n" ); document.write( "32760/24 = 1365 possibilities. \n" ); document.write( "---------------- \n" ); document.write( "This is 15!/((15-4)!*4!) \n" ); document.write( "! is factorial, and it's on most calculators. \n" ); document.write( " |