document.write( "Question 187388: 2x+3y= 12 and x+y=4\r
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\n" ); document.write( "\n" ); document.write( "answer (0,4)
\n" ); document.write( " need a break down of how my text book got this answer
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Algebra.Com's Answer #140454 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "Given\"system%282x%2B3y=+12%28EQN1%29%2Cx%2By=4%28EQN2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "In EQN 2 we get--->\"y=4-x\", EQN 3, which we subst. in EQN 1:
\n" ); document.write( "\"2x%2B3%28highlight%284-x%29%29=12\"
\n" ); document.write( "\"2x%2B12-3x=12\"---->\"3x-2x=12-12\"---->\"red%28x=0%29\"
\n" ); document.write( "Substitute x=0 in EQN 3:
\n" ); document.write( "\"y=4-0\"----->\"red%28y=4%29\"
\n" ); document.write( "There you go, Point of Intersection (0,4).
\n" ); document.write( "See graph to verify:
\n" ); document.write( "---> RED Line (EQN 1); GREEN Line (EQN 2)
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo

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