document.write( "Question 26118: I'm having with this problems also. \r
\n" ); document.write( "\n" ); document.write( "The second ngle of a triangular building lot is three times as large as the first. The third angle is 10 degree more than the sum of the other two angles. Find the measure of the third angle. \r
\n" ); document.write( "\n" ); document.write( "I also tried this one out and didn't know where to start. so far i got:
\n" ); document.write( "x+3x+10=180\r
\n" ); document.write( "\n" ); document.write( "when i worked out the problem, it didn't look like the right answer. Please help!
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Algebra.Com's Answer #14043 by mathrebel(25)\"\" \"About 
You can put this solution on YOUR website!
the sum of the three angles is 180
\n" ); document.write( "angle 1 = x
\n" ); document.write( "angle 2 = 3*x
\n" ); document.write( "angle 3 = (x+3*x)+10 --> u need to include the sum of the other two angles.
\n" ); document.write( "x+3x+(x+3x)+10=180
\n" ); document.write( "8x+10=180
\n" ); document.write( "8x=170
\n" ); document.write( "x=21.25\r
\n" ); document.write( "\n" ); document.write( "the third angle is (x+3x)+10=21.25+3*21.25+10=95
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