document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187310>Question 187310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average of nine numbers is 40. If 1 is added to the first number, 2 is added to the second number, 3 is added to the third number and so on up to the ninth number, what is the new average? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140420 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "If the average of 9 numbers is 40, then the sum of the nine numbers must be 9 times 40 or 360.  If you add 1 to the first number, 2 to the second, and so on, then you must be adding:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \  \sum_{i=1}^9\, i = \frac{(1 + 9)9}{2} = 45\">\r<BR>\n" );
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document.write( "So the sum is 360 + 45 = 405, and the new average is 405 divided by 9 = 45.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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