document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26120>Question 26120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the problem is:<BR>\n" );
document.write( "The sum of the measures of two complementary angles is 90 degree. If in angle measures 15 degree more than twice the measure of it's complement, find the measure of each angle. .\r<BR>\n" );
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document.write( "please help i'm really lost with this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14041 by </B><A HREF=/tutors/aboutme.mpl?userid=mathrebel><B>mathrebel(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathrebel><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of two angles is 90.<BR>\n" );
document.write( "first denote one angle as x<BR>\n" );
document.write( "then the other one, will be: measures 15 degree more than twice the measure of it's complement--> 15 + 2x\r<BR>\n" );
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document.write( "so the final equation is the first angle + the second angle=90 :<BR>\n" );
document.write( "x + 15+2x = 90\r<BR>\n" );
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document.write( "3x+15=90\r<BR>\n" );
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document.write( "3x=75\r<BR>\n" );
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document.write( "x=25 which is the first angle\r<BR>\n" );
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document.write( "and the second one is 2*25+15=65     \r<BR>\n" );
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document.write( "check solution: 65+25=90 </SPAN>\n" );
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