document.write( "Question 26119: my problems is:
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document.write( "Sharon invested money in a saving account at a rate of 6% simple interest. After 1 yr, she has $6996 in the account. How much did sharn originally invest. \r
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document.write( "For some reason i cannot get this at al. My equation that i got so far is : 0.06x+12=6996
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document.write( "when i worked out the proble it gave me a big number so i knew it wasn't right. i tried switching the numbers around, but the answer i come up with still doesn't look right. please help! \n" );
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Algebra.Com's Answer #14040 by mathrebel(25)![]() ![]() ![]() You can put this solution on YOUR website! $6996 is whatever sharon invested plus the 6% interest, so the equations is \n" ); document.write( "0.06*x+x=6996 \n" ); document.write( "1.06*x=6996 \n" ); document.write( "x=(6996/1.06)=6600\r \n" ); document.write( "\n" ); document.write( "One way to check the solution is right is to work backwards; \n" ); document.write( "0.06*(6600)+6600=6996 \n" ); document.write( " |