document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187151>Question 187151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I NEED HELP IN STATISTICS. PLEASE HELP. THANK YOU SO MUCH.\r<BR>\n" );
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document.write( " Quality Polls contends that an agent conducts a mean of 53 in-depth home surveys every week. A streamlined survey form has been introduced, and the pollster wants to evaluate its effectiveness. A random sample of 17 agents showed their total number of surveys conducted during a week.<BR>\n" );
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document.write( "53<BR>\n" );
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document.write( "53<BR>\n" );
document.write( "54<BR>\n" );
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document.write( "At the .05 level of significance, can we conclude that the mean number of interviews conducted by the agents is more than 53 per week? Why? Explain your decision on the null hypothesis.<BR>\n" );
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document.write( "Hypothesis Test: Mean vs. Hypothesized Value<BR>\n" );
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document.write( " 	53.000 	hypothesized value	 	 <BR>\n" );
document.write( " 	56.882 	mean Data	 	 <BR>\n" );
document.write( " 	3.199 	std. dev.	 	 	 <BR>\n" );
document.write( " 	0.776 	std. error	 	 	 <BR>\n" );
document.write( " 	17 	n	 	 	 <BR>\n" );
document.write( " 	16 	df	 	 	 <BR>\n" );
document.write( " 	 	 	 	 	 <BR>\n" );
document.write( " 	5.00	 t	 	 	 <BR>\n" );
document.write( " 	.0001	 p-value (one-tailed, upper)	 <BR>\n" );
document.write( " 	 	 	 	 	 <BR>\n" );
document.write( " 	55.237 	confidence interval 95.% lower	 <BR>\n" );
document.write( " 	58.527 	confidence interval 95.% upper	 <BR>\n" );
document.write( " 	1.645 	   half-width	 	 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140388 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At the .05 level of significance, can we conclude that the mean number of interviews conducted by the agents is more than 53 per week? Why? Explain your decision on the null hypothesis.\r<BR>\n" );
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document.write( "Hypothesis Test: Mean vs. Hypothesized Value\r<BR>\n" );
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document.write( "53.000 hypothesized value <BR>\n" );
document.write( "56.882 mean Data <BR>\n" );
document.write( "3.199 std. dev. <BR>\n" );
document.write( "0.776 std. error <BR>\n" );
document.write( "17 n <BR>\n" );
document.write( "16 df \r<BR>\n" );
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document.write( "5.00 t <BR>\n" );
document.write( ".0001 p-value (one-tailed, upper) \r<BR>\n" );
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document.write( "55.237 confidence interval 95.% lower <BR>\n" );
document.write( "58.527 confidence interval 95.% upper <BR>\n" );
document.write( "1.645 half-width <BR>\n" );
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document.write( "Ho: u(daily) = 53<BR>\n" );
document.write( "Ha: u(daily) > 53<BR>\n" );
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document.write( "Conclusion: since the p-value is less than 5%, reject Ho.<BR>\n" );
document.write( "The test provided evidence that the agent's daily average is greater than 53. <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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