document.write( "Question 187137: The length of a rectangle is 2 cm more than four times the width. If the perimeter of the rectangle is 34 cm, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #140350 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! \"length of a rectangle is 2 cm more than four times the width\" ---> L=4W+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"the perimeter of the rectangle is 34 cm\" ---> P=2L+2W ---> 34=2L+2W\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "34=2L+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "34=2(4W+2)+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "34=8W+4+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "34-4=8W+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30=10W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W=3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=4W+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=4(3)+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=12+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ans: length = 14 cm, width = 3 cm \n" ); document.write( " \n" ); document.write( " |