document.write( "Question 187182: 10^log^(2x+7) = 8 \n" ); document.write( "
Algebra.Com's Answer #140337 by 543210aaa(2)\"\" \"About 
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You may use the following rule:
\n" ); document.write( "\"m%5E%28log%28m%2Ca%29%29=a\"\r
\n" ); document.write( "\n" ); document.write( "Using this LHS of the question becomes 2x+7.
\n" ); document.write( "=>2x+7=8
\n" ); document.write( "=>2x=1
\n" ); document.write( "=>x=1/2\r
\n" ); document.write( "\n" ); document.write( "Satisfied???
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