document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187187>Question 187187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boy is 8 years older than his siter in ten years time, the ratio of their ages will be 3:2.what is the boys present age.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140324 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the boy is b years and his sister s years<BR>\n" );
document.write( "Given b = s + 8     ----  eqn (1)<BR>\n" );
document.write( "After 10 years boy’s age = b+10 and his sister’s age = s+10<BR>\n" );
document.write( "Given (b+10)/(s+10)   = 3/2<BR>\n" );
document.write( "Cross multiplying we get<BR>\n" );
document.write( "2(b+10) = 3(s+10)<BR>\n" );
document.write( "2b + 20 = 3s + 30<BR>\n" );
document.write( "2b – 3s = 10 plugging in the value of b from eqn(1) we get<BR>\n" );
document.write( "2(s+8) – 3s = 10<BR>\n" );
document.write( "2s + 16 – 3s = 10<BR>\n" );
document.write( "So  - s = - 6 therefore the sister is 6 years old and the boy is( 6+8 )= 14 years old\r<BR>\n" );
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document.write( "If you still require further clarifications please write to udayakumar.t.r@gmail.com<BR>\n" );
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