document.write( "Question 26019: Members of the Ski Club contributed equally to obtain $1800 for a holiday trip. When 6 members found that they could not go, their contributions were refunded and each remaining member then had to pay $10 more to raise the $1800. How many went on the trip?\r
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Algebra.Com's Answer #14032 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let number going originally be \"x\". \n" ); document.write( "Each must have paid 1800/x \n" ); document.write( "If six dropped out that would be 6(1800/x) \n" ); document.write( "The remaining group numbers \"x-6\". \n" ); document.write( "EQUATION: \n" ); document.write( "1800-6(1800/x)+(x-6)10=1800 \n" ); document.write( " 6(1800/x)=10(x-6) \n" ); document.write( " 10800=10x^2-60x \n" ); document.write( "Divide by 10 to get: \n" ); document.write( " x^2-6x-1080=0 \n" ); document.write( " (x-36)(x+30)=0 \n" ); document.write( " x=36 \n" ); document.write( "There were originally 36 in the group.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |