document.write( "Question 26019: Members of the Ski Club contributed equally to obtain $1800 for a holiday trip. When 6 members found that they could not go, their contributions were refunded and each remaining member then had to pay $10 more to raise the $1800. How many went on the trip?\r
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Algebra.Com's Answer #14032 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let number going originally be \"x\".
\n" ); document.write( "Each must have paid 1800/x
\n" ); document.write( "If six dropped out that would be 6(1800/x)
\n" ); document.write( "The remaining group numbers \"x-6\".
\n" ); document.write( "EQUATION:
\n" ); document.write( "1800-6(1800/x)+(x-6)10=1800
\n" ); document.write( " 6(1800/x)=10(x-6)
\n" ); document.write( " 10800=10x^2-60x
\n" ); document.write( "Divide by 10 to get:
\n" ); document.write( " x^2-6x-1080=0
\n" ); document.write( " (x-36)(x+30)=0
\n" ); document.write( " x=36
\n" ); document.write( "There were originally 36 in the group.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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