document.write( "Question 187133This question is from textbook Precalculus
\n" ); document.write( ": How do I find the zeroes of a function of f(x)= -x squared plus 3x plus 6 ? \n" ); document.write( "
Algebra.Com's Answer #140273 by jim_thompson5910(35256)\"\" \"About 
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\"f%28x%29=+-x%5E2%2B3x%2B6\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"0=-x%5E2%2B3x%2B6\" Plug in \"f%28x%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2-3x-6\" Multiply EVERY term by -1 to make the leading coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=1\", \"b=-3\", and \"c=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-6%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=-3\", and \"c=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-6%29+%29%29%2F%282%281%29%29\" Negate \"-3\" to get \"3\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-4%281%29%28-6%29+%29%29%2F%282%281%29%29\" Square \"-3\" to get \"9\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9--24+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-6%29\" to get \"-24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9%2B24+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%289--24%29\" as \"sqrt%289%2B24%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+33+%29%29%2F%282%281%29%29\" Add \"9\" to \"24\" to get \"33\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+33+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2Bsqrt%2833%29%29%2F%282%29\" or \"x+=+%283-sqrt%2833%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%283%2Bsqrt%2833%29%29%2F%282%29\" or \"x+=+%283-sqrt%2833%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=4.372\" or \"x=-1.372\"
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