document.write( "Question 187089: Fred bicycles 7km/h slower than samantha. In the time it takes fred to bicycle 40km, samantha travels 68km. How fast does fred bicycles? \n" ); document.write( "
Algebra.Com's Answer #140235 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Fred's trip:\r
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\n" ); document.write( "\n" ); document.write( "d = 40 km, t unknown, but the same as Samantha's trip, r = Fred's rate of speed -- the answer we seek.\r
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\n" ); document.write( "\n" ); document.write( "Samantha's trip:\r
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\n" ); document.write( "\n" ); document.write( "d = 68 km, t unknown, but the same as Fred's trip, r = Fred's rate of speed so r + 7 = Samantha's rate of speed.\r
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\n" ); document.write( "\n" ); document.write( "For Fred:\r
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\n" ); document.write( "\n" ); document.write( "For Samantha:\r
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\n" ); document.write( "\n" ); document.write( "But t = t, so:\r
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\n" ); document.write( "\n" ); document.write( "Solve for r to get Fred's speed. Hint: First cross-multiply.\r
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