document.write( "Question 187079This question is from textbook algebra2
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document.write( ": Find all of the rational zeros of each function\r
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document.write( "26. p(x)= x^3+3x^2-25x+21\r
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document.write( "p= (+or-)1, (+or-)3, (+or-)7, (+or-)21\r
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document.write( "q= (+or-)1\r
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document.write( "1/1 1/3, 1/7, 1/21 \n" );
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Algebra.Com's Answer #140229 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Any rational zero can be found through this equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So let's list the factors of 21 (the last coefficient):\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let's list the factors of 1 (the first coefficient):\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let's divide each factor of the last coefficient by each factor of the first coefficient\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now simplify\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These are all the distinct rational zeros of the function that could occur\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: these are all of the possible roots. To find the actual rational roots (if there are any), you need to plug each possible root into the given polynomial. If you get a result of 0, then the corresponding input is a zero. \n" ); document.write( " |