document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187044>Question 187044</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780618851881/algebrahomeworkh>College Algebra A Graphing Approach</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I'm stuck on this problem, the 1 part oil in the problem is giving me a problem.\r<BR>\n" );
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document.write( "Mixture Problem<BR>\n" );
document.write( "A forester mixies gasoline and oil to make 2 gallons of mixture for his two-cycle chainsaw engine. This mixture is 32 parts gasoline and 1 part oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140207 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=amount of gas that needs to be added\r<BR>\n" );
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document.write( "Since we are only adding gas, the amount of oil before we add the gas (2/32) is the same as the amount of oil after we add the gas ((2+x)/40), so:\r<BR>\n" );
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document.write( "2/32=(2+x)/40=<BR>\n" );
document.write( "1/16=(2+x)/40  multiply each side by 80<BR>\n" );
document.write( "5=2(2+x);<BR>\n" );
document.write( "5=4+2x<BR>\n" );
document.write( "2x=1<BR>\n" );
document.write( "x=1/2 gal-----------------amount of gas that needs to be added<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "2/32=2.5/40<BR>\n" );
document.write( "1/16=1/16\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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