document.write( "Question 187050: what annual interest rate is needed for a principal of $3000 to grow to $5500 in three years \n" ); document.write( "
Algebra.Com's Answer #140203 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! what annual interest rate is needed for a principal of $3000 to grow to $5500 in three years \n" ); document.write( "------------------------- \n" ); document.write( "Interest = Prt \n" ); document.write( "---------------------\r \n" ); document.write( "\n" ); document.write( "Your interest is 5500-3000 = 2500 \n" ); document.write( "--------------------- \n" ); document.write( "2500 = 3000r*3 \n" ); document.write( "r = 2500/9000 \n" ); document.write( "r = 0.2778 \n" ); document.write( "rate = 27.78% \n" ); document.write( "-------------------------------- \n" ); document.write( " \n" ); document.write( " |