document.write( "Question 187050: what annual interest rate is needed for a principal of $3000 to grow to $5500 in three years \n" ); document.write( "
Algebra.Com's Answer #140203 by stanbon(75887)\"\" \"About 
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what annual interest rate is needed for a principal of $3000 to grow to $5500 in three years
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\n" ); document.write( "Interest = Prt
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\n" ); document.write( "\n" ); document.write( "Your interest is 5500-3000 = 2500
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\n" ); document.write( "2500 = 3000r*3
\n" ); document.write( "r = 2500/9000
\n" ); document.write( "r = 0.2778
\n" ); document.write( "rate = 27.78%
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