document.write( "Question 187011: x + y + z = 2
\n" );
document.write( "x - y + z = 1
\n" );
document.write( "x - y - z = 1
\n" );
document.write( " solve for x, y and z \n" );
document.write( "
Algebra.Com's Answer #140174 by sowmya(32)![]() ![]() ![]() You can put this solution on YOUR website! equation 1 + equation 2 \n" ); document.write( "=> 2(x+z) = 3 \n" ); document.write( " x+z = 3/2 \n" ); document.write( "equation 1 +equation3 \n" ); document.write( "=>2x = 3 \n" ); document.write( "=> x = 3/2\r \n" ); document.write( "\n" ); document.write( "equation 2+quation3 \n" ); document.write( "=> 2(x-y) =1 \n" ); document.write( " x-y = 1/2 \n" ); document.write( "y = 1\r \n" ); document.write( "\n" ); document.write( "equationj 1 substitute the values of x and y \n" ); document.write( "=>z=-1/2 \n" ); document.write( " |