document.write( "Question 187011: x + y + z = 2
\n" ); document.write( "x - y + z = 1
\n" ); document.write( "x - y - z = 1
\n" ); document.write( " solve for x, y and z
\n" ); document.write( "

Algebra.Com's Answer #140174 by sowmya(32)\"\" \"About 
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equation 1 + equation 2
\n" ); document.write( "=> 2(x+z) = 3
\n" ); document.write( " x+z = 3/2
\n" ); document.write( "equation 1 +equation3
\n" ); document.write( "=>2x = 3
\n" ); document.write( "=> x = 3/2\r
\n" ); document.write( "\n" ); document.write( "equation 2+quation3
\n" ); document.write( "=> 2(x-y) =1
\n" ); document.write( " x-y = 1/2
\n" ); document.write( "y = 1\r
\n" ); document.write( "\n" ); document.write( "equationj 1 substitute the values of x and y
\n" ); document.write( "=>z=-1/2
\n" ); document.write( "
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