document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186982>Question 186982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a) Find the area of a trapezoid with a height of 9 m and bases of 7 m and 25 m  b) Find the perimeter of a parallelogram with sides measuring 6.5 m and 3.5 m\r<BR>\n" );
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document.write( "Please help me figure these problems out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140172 by </B><A HREF=/tutors/aboutme.mpl?userid=sowmya><B>sowmya(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sowmya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trapezoid will consist of a rectangle with breadth = 9m (height of trapezoid)<BR>\n" );
document.write( "and two right traingles one of side of each will be teh height of trapezoid viz 9m and the base add upto 18m(25m (one side fo tapezoid)-7m(the other side))<BR>\n" );
document.write( "Hence area of trapezoid = area of two triangles +area of rectangle <BR>\n" );
document.write( "                         =1/2 * base* height +1/2 * base* height + 9*7<BR>\n" );
document.write( "                         =(1/2*9)(base+base) +63<BR>\n" );
document.write( "                         =81 +63<BR>\n" );
document.write( "                         = 144 sq m\r<BR>\n" );
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document.write( "Perimter = sum of all sides = 2(6.5+3) m = 19m\r<BR>\n" );
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