document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187008>Question 187008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> raphael can load a large shipping truck in 15 hours. working together, raphael and jana can load the same truck in 6 hours. how long would it take to load the truck by herself?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140169 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use equation \r<BR>\n" );
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document.write( "t(1/rate1 + 1/rate2) = 1\r<BR>\n" );
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document.write( "rate1 = raphael's rate = 15 hrs, rate2 = janas rate = x \r<BR>\n" );
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document.write( "t(1/15+1/x)=1\r<BR>\n" );
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document.write( "t is given as t=6\r<BR>\n" );
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document.write( "----> 6(1/15+1/x)=1\r<BR>\n" );
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document.write( "1/15+1/x=1/6\r<BR>\n" );
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document.write( "2x+30=5x\r<BR>\n" );
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document.write( "30=3x\r<BR>\n" );
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document.write( "x=10\r<BR>\n" );
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document.write( "Ans: jana can load the truck in 10 hrs </SPAN>\n" );
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