document.write( "Question 186994: 2y^ 2 -6y= 3 \n" ); document.write( "
Algebra.Com's Answer #140152 by stanbon(75887)\"\" \"About 
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2y^ 2 -6y= 3
\n" ); document.write( "2y^2 -6y -3 = 0
\n" ); document.write( "---------
\n" ); document.write( "Use quadratic equation:
\n" ); document.write( "y = [6 +- sqrt(36 - 4*2*-3)]/4\r
\n" ); document.write( "\n" ); document.write( "y = [6 +- sqrt(60)]/4\r
\n" ); document.write( "\n" ); document.write( "y = [6 +- 2sqrt(15)]/4\r
\n" ); document.write( "\n" ); document.write( "y = [3 +- sqrt(15)]/2
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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