document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186957>Question 186957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a boat goes downstream 72 miles in 3 hours and upstream 60 miles in 6 hours, the rate of the river and the rate of the boat in still water respectively are?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140136 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the velocity of boat in still water  = b and velocity of river = r<BR>\n" );
document.write( "Downstream velocity  =  b + r = 27/3 = 24 mph  <BR>\n" );
document.write( "Upstream velocity = b – r = 60/10 = 10 mph<BR>\n" );
document.write( "Adding the above two equations we get 2b = 24 + 10 = 34<BR>\n" );
document.write( "So b  34/2 = 17 mph.  Plugging this value into the first equation we get <BR>\n" );
document.write( "17+ r = 24 ;  r = 24 – 17 = 7 mph\r<BR>\n" );
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document.write( "Answer is the river flows at 7 miles per hour and the boat goes in still water at the rate of 17 miles per hour\r<BR>\n" );
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document.write( "If you still require further clarifications please write to:<BR>\n" );
document.write( "udayakumar.t.r@gmail.com </SPAN>\n" );
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