document.write( "Question 186873: PLEASE HELP!!
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document.write( "a mixture contains 40 ounces of glycol and water and 10% glycol.if the mixture is to be strengthened to 25%,how much glycol is to be added?\r
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document.write( "-what is the frist step?
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document.write( "-is a varible added for water and glycol or for just glycol?
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document.write( "-does it invole cross multipling? \n" );
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Algebra.Com's Answer #140116 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A mixture contains 40 ounces of glycol and water and 10% glycol. \n" ); document.write( "If the mixture is to be strengthened to 25%, how much glycol is to be added? \n" ); document.write( ": \n" ); document.write( "First step \n" ); document.write( "let x = amt of glycol required \n" ); document.write( "; \n" ); document.write( "Write a percent glycol equation. (Pure glycol = 1.0x) \n" ); document.write( ".10(40) + x = .25(x + 40) \n" ); document.write( ": \n" ); document.write( "4 + x = .25x + 10 \n" ); document.write( ": \n" ); document.write( "x - .25x = 10 - 4 \n" ); document.write( ": \n" ); document.write( ".75x = 6 \n" ); document.write( "x = \n" ); document.write( "x = 8 oz of glycol required \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution in the equation (48 oz resulting total) \n" ); document.write( ".1(40) + 8 = .25(48) \n" ); document.write( "4 + 8 = 12 \n" ); document.write( "; \n" ); document.write( "How about this? Did it make sense to you? \n" ); document.write( " |