document.write( "Question 186943: please help me solve by factoring.
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\n" ); document.write( "4x^2-11x+6=0 and show work so i can do this on my own tomorrow. thanks
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Algebra.Com's Answer #140114 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, factor \"4x%5E2-11x%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"4x%5E2-11x%2B6\", we can see that the first coefficient is \"4\", the second coefficient is \"-11\", and the last term is \"6\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"4\" by the last term \"6\" to get \"%284%29%286%29=24\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"24\" (the previous product) and add to the second coefficient \"-11\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"24\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"24\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,8,12,24\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-8,-12,-24\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"24\".\r
\n" ); document.write( "\n" ); document.write( "1*24
\n" ); document.write( "2*12
\n" ); document.write( "3*8
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\n" ); document.write( "(-1)*(-24)
\n" ); document.write( "(-2)*(-12)
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-11\":\r
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First NumberSecond NumberSum
1241+24=25
2122+12=14
383+8=11
464+6=10
-1-24-1+(-24)=-25
-2-12-2+(-12)=-14
-3-8-3+(-8)=-11
-4-6-4+(-6)=-10
\r
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-3\" and \"-8\" add to \"-11\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-3\" and \"-8\" both multiply to \"24\" and add to \"-11\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-11x\" with \"-3x-8x\". Remember, \"-3\" and \"-8\" add to \"-11\". So this shows us that \"-3x-8x=-11x\".\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2Bhighlight%28-3x-8x%29%2B6\" Replace the second term \"-11x\" with \"-3x-8x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%5E2-3x%29%2B%28-8x%2B6%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%284x-3%29%2B%28-8x%2B6%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%284x-3%29-2%284x-3%29\" Factor out \"2\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%284x-3%29\" Combine like terms. Or factor out the common term \"4x-3\"\r
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\n" ); document.write( "\n" ); document.write( "So \"4x%5E2-11x%2B6\" factors to \"%28x-2%29%284x-3%29\".\r
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\n" ); document.write( "\n" ); document.write( "So \"4x%5E2-11x%2B6=0\" becomes \"%28x-2%29%284x-3%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero (by the use of the zero product property):\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0\" or \"4x-3=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=3%2F4\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are\r
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\n" ); document.write( "\n" ); document.write( " \"x=2\" or \"x=3%2F4\"
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