document.write( "Question 186933: You wish to mix wine with 25% alcohol and peach schnapps with 50% alcohol to obtain a different drink. How many liters of wine would you need to make 20 liters of the mixture with a 40% alcohol content?\r
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document.write( "Could you help me set up the table to solve this I'm completely lost and I don't know where to put what in the table and what to do with it afterword. \n" );
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Algebra.Com's Answer #140109 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Ok, YOU DO THE TABLE AND I WILL SET UP THE EQUATION :\r \n" ); document.write( "\n" ); document.write( "Let x= amount of wine needed \n" ); document.write( "Then 20-x=amount of peach schnapps needed\r \n" ); document.write( "\n" ); document.write( "Amount of pure alcohol before the mixture = amount of pure alcohol after they are mixed, so: \n" ); document.write( "0.25x + 0.50(20-x)=0.40*20 get rid of parens \n" ); document.write( "0.25x+10-0.50x=8 subtract 10 from each side \n" ); document.write( "0.25x+10-10-0.50x=8-10 collect like terms \n" ); document.write( "-0.25x=-2 divide each side by -0.25 \n" ); document.write( "x=8 liters-----------amount of wine needed\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "8*0.25+0.50*12=0.40*20 \n" ); document.write( "2+6=8 \n" ); document.write( "8=8\r \n" ); document.write( "\n" ); document.write( "Now you could solve this problem using two unknowns: \n" ); document.write( "Let x=amount of wine \n" ); document.write( "y=amount of schnapps \n" ); document.write( "x+y=20------------------------eq1 \n" ); document.write( "0.25x+0.50y=0.40*20 or \n" ); document.write( "0.25x+0.50y=8--------------------eq2\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |