document.write( "Question 186887: The longer leg of a right triangle measures two feet more than twice the length of the shorter leg. The hypotenuse measures 3 feet more than twice the shorter leg. Find the length of all three sides. \n" ); document.write( "
Algebra.Com's Answer #140088 by uday1435(57)\"\" \"About 
You can put this solution on YOUR website!
The longer leg of a right triangle measures two feet more than twice the length of the shorter leg. The hypotenuse measures 3 feet more than twice the shorter leg. Find the length of all three sides.\r
\n" ); document.write( "\n" ); document.write( "Let the shorter leg = s
\n" ); document.write( "Longer leg = 2s + 2
\n" ); document.write( "Hypotenuse = 2s+3
\n" ); document.write( "By Pythagorean theorem
\n" ); document.write( "(2s + 3)^2 = (2s+2)^2 + s^2
\n" ); document.write( "4s^2+12s + 9 = 4s^2 + 8s +4 + s^2
\n" ); document.write( "On simplification we get s^2 – 4s – 5 = 0
\n" ); document.write( "(s – 5) (s + 1) = 0
\n" ); document.write( "So s = 5, means The shorter leg = 5 feet , Longer leg = 2(5)+2 = 12 feet and the hypotenuse = 2(5) + 3 = 13 feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you still require further clarifications please write to udayakumar.t.r@gmail.com
\n" ); document.write( "
\n" ); document.write( "
\n" );