![\"\"](\"/images/stars/stars-13.gif\")
You can put this solution on YOUR website!
the tens digit of a two-digit number exceeds twice the units digit by 1.
\n" ); document.write( " if the digits are reversed, the sum of the new number and the original
\n" ); document.write( " number is 143. find the original number.
\n" ); document.write( ":
\n" ); document.write( "Let x = the 10's digit
\n" ); document.write( "Let y = the units
\n" ); document.write( "then
\n" ); document.write( "10x + y = the number
\n" ); document.write( ":
\n" ); document.write( "\"the tens digit of a two-digit number exceeds twice the units digit by 1.\"
\n" ); document.write( "x = 2y + 1
\n" ); document.write( "or
\n" ); document.write( "x - 2y = 1
\n" ); document.write( ":
\n" ); document.write( "\"if the digits are reversed, the sum of the new number and the original number is 143.\"
\n" ); document.write( "(10y + x) + (10x + y) = 143
\n" ); document.write( "10y + x + 10x + y = 143
\n" ); document.write( "11x + 11y = 143
\n" ); document.write( "Simplify, divide equation by 11
\n" ); document.write( "x + y = 13
\n" ); document.write( ":
\n" ); document.write( "Subtract the 1st equation
\n" ); document.write( "x + y = 13
\n" ); document.write( "x - 2y = 1
\n" ); document.write( "-------------eliminates x
\n" ); document.write( "0x + 3y = 12
\n" ); document.write( "y = 4
\n" ); document.write( "then
\n" ); document.write( "x = 2(4) + 1
\n" ); document.write( "x = 9
\n" ); document.write( ";
\n" ); document.write( "94 = the number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "if the digits are reversed, the sum of the new number and the original number is 143.
\n" ); document.write( "49 + 94 = 143 \n" ); document.write( "