document.write( "Question 186849: If the length of a rectangle is 3 feet longer than the width and the diagonal is 15 feet, then what are the length and the width? \n" ); document.write( "
Algebra.Com's Answer #140069 by vleith(2983)\"\" \"About 
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Let width be w. Then Length is (w+3)
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\" pythagorean theorem
\n" ); document.write( "\"w%5E2+%2B+%28w%2B3%29%5E2+=+15%5E2\"
\n" ); document.write( "\"w%5E2+%2B+w%5E2+%2B+6w+%2B+9+=+225\"
\n" ); document.write( "\"2w%5E2+%2B+6w+-+216+=+0\"
\n" ); document.write( "\"2%28w-9%29%28w%2B12%29+=+0\"
\n" ); document.write( "w = 9 or w = -12. Since a width cannot be negative, then w = 9. And length = 12\r
\n" ); document.write( "\n" ); document.write( "Notice the triangle formed by width:length:diagonal is in the ration 3:4:5 -- a common ratio for right triangles and one you would do well to 'recognize on sight'.
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