document.write( "Question 186854: A plane takes 6 hours to fly from San Francisco to New York, and 5 hours to return back. The wind velocity is 50 miles per hour, from New York to San Francisco. What is the speed of the airplane.\r
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\n" ); document.write( "\n" ); document.write( "can you solve this for me? \n" ); document.write( "
Algebra.Com's Answer #140065 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=rate (speed) or the plane in still air
\n" ); document.write( "Then r+50=rate of plan with the wind (return trip)
\n" ); document.write( "And r-50=rate of plane against the wind (SF to NY)\r
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\n" ); document.write( "\n" ); document.write( "time to fly to NY:
\n" ); document.write( "6=d/(r-50)-----------------eq1
\n" ); document.write( "time to return:
\n" ); document.write( "5=d/(r+50)-----------------eq2
\n" ); document.write( "from eq1, d=6(r-50). Substitute this into eq2 for d
\n" ); document.write( "5=6(r-50)/(r+50) multiply each side by (r+50)
\n" ); document.write( "5(r+50)=6(r-50) get rid of parens
\n" ); document.write( "5r+250=6r-300 add 300 to and subtract 5r from both sides
\n" ); document.write( "250+300+5r-5r=6r-5r-300+300 collect like terms
\n" ); document.write( "r=550 mph---------------------speed of plane in still air\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "distance to SF=(550-50)*6=3000 mi
\n" ); document.write( "return distance=(550+50)*5=3000 mi
\n" ); document.write( "3000=3000\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "
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