document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186850>Question 186850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two-digit number is 6. if the digits are reversed, the new number is three times the original tens digit. find the original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140062 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"the sum of the digits of a two-digit number is 6\" ---> t+u=6 ---> t=6-u\r<BR>\n" );
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document.write( "\"if the digits are reversed, the new number is three times the original tens digit\" 10u+t=3t\r<BR>\n" );
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document.write( "10u+t=3t\r<BR>\n" );
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document.write( "10u=2t\r<BR>\n" );
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document.write( "10u=2(6-u)\r<BR>\n" );
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document.write( "10u=12-2u\r<BR>\n" );
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document.write( "12u=12\r<BR>\n" );
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document.write( "u=1\r<BR>\n" );
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document.write( "t=6-u\r<BR>\n" );
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document.write( "t=6-1\r<BR>\n" );
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document.write( "t=5\r<BR>\n" );
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document.write( "Original Number: 51 </SPAN>\n" );
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