document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186747>Question 186747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The A train goes 12mph slower than the E train. The A train travels 230mi in the same time that the E train travels 290mi. Find the speed of each train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140060 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of A train = v mph then speed of E train = v+12 mph<BR>\n" );
document.write( "speed = distance/time so time = distance/speed\r<BR>\n" );
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document.write( "Applying the given conditions 230/v = 290/(v+12)<BR>\n" );
document.write( "Cross multiplying we get<BR>\n" );
document.write( "230v + 12(230) = 290v<BR>\n" );
document.write( "(290- 230)v = 12(230)<BR>\n" );
document.write( "60 v =12(230)<BR>\n" );
document.write( "v = 46 mph <BR>\n" );
document.write( "So the A train is 46 mph and E Train is  58 mph  (46+12 = 58)\r<BR>\n" );
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document.write( "If you still require further clarifications please write to udayakumar.t.r@gmail.com </SPAN>\n" );
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