document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186827>Question 186827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, Here is my question:\r<BR>\n" );
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document.write( "A father and son have a joint age of 36. The father is 30 years older than his son. How old is his son? Clue: the answer is not 6.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140051 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let fathers age = f and sons age be s\r<BR>\n" );
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document.write( "Given  f+s = 36 and f – s = 30\r<BR>\n" );
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document.write( "f + s = 36<BR>\n" );
document.write( "f – s = 30    		adding these equations we get<BR>\n" );
document.write( "2f = 66         	since +s and –s cancels while adding. <BR>\n" );
document.write( "f = 66/2 = 33     	Dividing the eqn by 2<BR>\n" );
document.write( "Now plug in the value of f into equation 1 we get<BR>\n" );
document.write( "33 + s = 36		subtracting 33 from both sides of this equation<BR>\n" );
document.write( "s = 36 – 33 = 3      \r<BR>\n" );
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document.write( "So the answer is  father is 33 years and son is 3 years old\r<BR>\n" );
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document.write( "If you still require further clarifications please write to udayakumar.t.r@gmail.com<BR>\n" );
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