document.write( "Question 186838: Twice the difference of a number and three is greater than or equal to the number increased by five. Find the solution. \n" ); document.write( "
Algebra.Com's Answer #140050 by jim_thompson5910(35256)\"\" \"About 
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\"Twice the difference of a number and three is greater than or equal to the number increased by five\" translates to \"2%28x-3%29%3E=x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x-3%29%3E=x%2B5\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-6%3E=x%2B5\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3E=x%2B5%2B6\" Add \"6\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-x%3E=5%2B6\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=5%2B6\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=11\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x%3E=11\"\r
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\n" ); document.write( "\n" ); document.write( "This means that 11 or any other larger number will satisfy the statement.
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