document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186781>Question 186781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain trip took 40 min to complete. If half the distance was 100 and the other half at 60, what's the distance traveled during the trip?<BR>\n" );
document.write( "a) 68 b) 50<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140022 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "T=D/R<BR>\n" );
document.write( "2/3=(D/2)/100+(D/2)/60<BR>\n" );
document.write( "2/3=D/2*1/100+D/2*1/60<BR>\n" );
document.write( "2/3=D/200+D/120<BR>\n" );
document.write( "2/3=(120D+200D)/(200*120)<BR>\n" );
document.write( "2/3=320D/24,000<BR>\n" );
document.write( "3*320D=2*24,000<BR>\n" );
document.write( "960D=48,000<BR>\n" );
document.write( "D=48,000/960<BR>\n" );
document.write( "D=50 MILES IS THE DISTANCE OF THE TRIP.\r<BR>\n" );
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