document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186758>Question 186758</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/032150108X/algebrahomeworkh>A Survey of Mathematics with Application</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter and area of a right triangle if the shortest side is 9cm and the longest side is 15cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140002 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The longest side is the hypotenuse. So  by Pythagorean Theorem, 15^2 = 9^2 + x^2<BR>\n" );
document.write( "where x is the unknown side\r<BR>\n" );
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document.write( "x^2  = 15^2 - 9^2  = 225 - 81 = 144<BR>\n" );
document.write( "so x  = sqrt(144) = 12 cms\r<BR>\n" );
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document.write( "The perimeter = sum of the length of all 3 sides = 12+15+9 = 36 cms\r<BR>\n" );
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document.write( "Area = 1/2 base x height = 1/2 x 12 x 9 = 54 sq cms\r<BR>\n" );
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