document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186759>Question 186759</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/032150108X/algebrahomeworkh>A Survey of Mathematics with Application</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> What is the circumference and area in feet of circular pool that has a diameter of 20 yards?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140000 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diameter = 20 yards <BR>\n" );
document.write( "radius r = 20/2 = 10 yards = 3 x 10 = 30 feet (since 3 ft = 1 yard)<BR>\n" );
document.write( "Circumference =  2 pi r = 2 x 3.14 x 30 = 188.4 feet<BR>\n" );
document.write( "Area = pi r^2  = 3.14 x 30 x 30 = 2827 sq. feet </SPAN>\n" );
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